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x=x^2+10-6
We move all terms to the left:
x-(x^2+10-6)=0
We get rid of parentheses
-x^2+x-10+6=0
We add all the numbers together, and all the variables
-1x^2+x-4=0
a = -1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-1)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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